In rhombus EFGH below, EF= 13m and DG = 5m, Find the area of the rhombus.
Be sure to include the correct unit in your answer.

the correct answer is 120 square meters

Step-by-step explanation:

DG is a half diagonal and it intersects with the other diagonal at 90°. So it forms a right angle triangle. Using Pythagoras theorem

13^2-5^2=d^2

169-25=d^2

144=d^2

d=√144

d=12

so the other half diagonal is 12m

the two diagonals will be 2×5 and 2×12

the two diagonals will be 10m and 24m

area of a rhombus=1/2d1d2

area of the rhombus= 1/2×10×24

area of the rhombus=120 square meters

step-by-step explanation:

the options are kind of confusing. i can tell you what i see going on here when i look at the graph.

the class and exam medians are closely related, and it looks like the low outlier on the exam did pull the median lower. [tex][/tex]

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

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