Jill is buying a chalk board and chalk markers. She can spend at most $42 for chalkboard and chalk markers. If chalkboard costs $18 and each chalk marker cost $4, write and solve an inequality to show the maximum number of chalk markers Jill can buy.

1. 18x + 4y ≤42

2. Jill can buy a maximum of 6 maker

Step-by-step explanation:

This problem bothers modeling of an inequality equation, which is quite simple provided the word problem can be stated Mathematically.

From the problem statement Jill is buying one chalkboard and many chalk makers

Let the number of chalkboard be x

And the number of makers be y

She can spend at most $42

The cost of one chalkboard is $18

And one maker is $4

The inequality expression is given as

18x + 4y ≤42,

we use the less than or equal to since Jill cannot spend more than $42

To solve for the maximum number of maker Jill can buy, we already know that the number of chalkboard is one

18*(1) +4y≤42

4y≤42-18

4y≤24

y≤24/4

y≤6

the sum of the lengths of any two sides of a triangle is greater than the length of the third side. if you take the three sides of a triangle and add them in pairs, the sum is greater than (not equal to) the third side. if that is not true, then it is not possible to construct a triangle with the given side lengths.

step-by-step explanation: