![2\sqrt[3]{x-7}+11=3](/tpl/images/0638/0784/b651b.png)
for x.![\begin{aligned}2\sqrt[3]{x-7}&=-8\\ \sqrt[3]{x-7}&=-4\\ \left(\sqrt[3]{x-7}\right)^3&=(-4)^3\\ x-7&=-64 \end{aligned}](/tpl/images/0638/0784/f7a9a.png)
Ahmed is solving the following equation for xxx.
2\sqrt[3]{x-7}+11=32
3
x−7...
Mathematics, 05.05.2020 12:55 miyah5316
Ahmed is solving the following equation for xxx.
2\sqrt[3]{x-7}+11=32
3
x−7
+11=32, cube root of, x, minus, 7, end cube root, plus, 11, equals, 3
His first few steps are given below.
\begin{aligned}2\sqrt[3]{x-7}&= -8\\ \\ \sqrt[3]{x-7}&=-4\\ \\ \left(\sqrt[3]{x-7}\right)^3&=( -4)^3\\ \\ x-7&=-64 \end{aligned}
2
3
x−7
3
x−7
(
3
x−7
)
3
x−7
=−8
=−4
=(−4)
3
=−64
Is it necessary for Ahmed to check his answers for extraneous solutions?
Choose 1
Answers: 3
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