The path of a football can be modelled by the equation, h=-10d2+120d , where h represents the height, in metres, of the football above the ground and d represents the horizontal distance, in metres, of the football from the player. At what horizontal distance does the football land?

12 m

Step-by-step explanation:

The path of a football has been modeled by the equation:

where h represents the height and d represents the horizontal distance.

When the ball lands, it means that its height is back at 0 metres. This means that we have to find horizontal distance, d, when height, h, is 0.

=>

∴ d = 0 m

and

10d - 120 = 0

=> d = 120 / 10 = 12 m

There are two solutions for d when h = 0 m.

The first solution (d = 0 m) is a case where the ball has not been thrown at all. This means the ball has not moved away from the football player and it is still on the ground.

The second solution is the answer to our problem (d = 12 m). The ball lands at a horizontal distance of 12 m

dalila is incorrect. the whisker on the left is very long, going all the way out to 5. the whisker goes from 5 to 30, so it has a spread of 25. the rest of the box plot values are closer together, so 5 is an outlier

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204