Find mJPK Geometry circles will mark brainliest

53.13

Step-by-step explanation:

mJKL = sin-1(9/15) = 36.9 deg

mKJL = = 36.9 deg ...base angles of isosceles triangle JKL

mJLK = 180 - 36.9 - 36.9 = 106.26 deg

mJPK = mJLK/2 = 106.29/2 = 53.1 deghalf of central angle

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this

b

step-by-step explanation:

a difference is the result of subtraction. while each of these expressions has subtraction in it, a difference will be the result when subtraction is the last operation applied in the order of operations for the expression. this means subtraction must be outside of the parenthesis. only b has this.