The amount of carbon-14 present in animal bones after t years is given by P(t)equalsUpper P 0 e Superscript negative 0.00012 t. A bone has lost 10% of its carbon-14. How old is the bone?

878 years

Step-by-step explanation:

The amount of carbon-14 present in animal bones after t years is given by:

If the bone has lost 10% of its carbon-14.

Its Initial Amount of C-14, =100%=1

Present Amount, P(t)=(100-10)%=90%=0.9

Substituting these values in the model

The bone is 878 years old.