Neil tossed a 6-sided die 90 times. The
results of his tosses are recorded in the
table below: If Neil tossed the die 135
times, predict the experimental probability
of rolling the number 3? (hint:set up a
proportion)
Number. Time Tossed
1. 13
2. 15
3. 14
4. 12
5. 18
6. 18

21

Step-by-step explanation:

Let's first get the probability that he had in rolling a 3 when he rolled the die 90 times. The formula for probability is times he got a 3 / times he rolled the die.

He got a 3 14 times, and he rolled 90 times, so the proportion is 14/90.

If we want to extend this proportion to when he rolls 135 times, we just multiply.

135 * 14/90 = 21 expected times he rolls a 3

the answer is mp

step-by-step explanation:

simplifying

5(x + -6) = 2(x + 3)

reorder the terms:

5(-6 + x) = 2(x + 3)

(-6 * 5 + x * 5) = 2(x + 3)

(-30 + 5x) = 2(x + 3)

reorder the terms:

-30 + 5x = 2(3 + x)

-30 + 5x = (3 * 2 + x * 2)

-30 + 5x = (6 + 2x)

solving

-30 + 5x = 6 + 2x

solving for variable 'x'.

move all terms containing x to the left, all other terms to the right.

add '-2x' to each side of the equation.

-30 + 5x + -2x = 6 + 2x + -2x

combine like terms: 5x + -2x = 3x

-30 + 3x = 6 + 2x + -2x

combine like terms: 2x + -2x = 0

-30 + 3x = 6 + 0

-30 + 3x = 6

add '30' to each side of the equation.

-30 + 30 + 3x = 6 + 30

combine like terms: -30 + 30 = 0

0 + 3x = 6 + 30

3x = 6 + 30

combine like terms: 6 + 30 = 36

3x = 36

divide each side by '3'.

x = 12

simplifying

x = 12

this should .