Consider the complex numbers p=1 - 3i and q = x + (2x + 1)i,
Find the values of x that satisfy the equation p = q

Solve the inequality Re(pg) +8 < (Im(pq))?

x = 1 - i(3 - 2x - 1)

Step-by-step explanation:

One question per post, please.

We want to solve the equation p = q, where p = 1 - 3i and q = x + (2x + 1)i.

Expanding q, we get q = x + 2xI + i, so that p + q becomes

1 - 3i = x + 2xi + i

Solving for x by subtracing (2xi + 1) from both sides, we get:

1 - 3i - 2xi - i = x

This result could be left as is, or we could separate the real and imaginary parts:

x = 1 - i(3 - 2x - 1)

the solution is the point

step-by-step explanation:

we have

> equation a

> equation b

adds equation a and equation b

substitute the value of x in equation b to find the value of y

the solution is the point