The graph of an absolute value function has a vertex at (-2,3) and passes through the point (-1,0). Using transformations of the parent function, has the graph been dilated by a scale factor other than 1

51

step-by-step explanation:

73-22=51 the   mass number minus the amount of protons gives you the amount of neutrons

step-by-step explanation:

the true ones are a b and d

34.5 cm

step-by-step explanation:

generally for a circular segment of angle, θ° and radius r

arc length

= (θ/360) x circumference

= (θ/360) x 2πr

in our case, θ = 60°, π=3.142 and r = 33 cm

substitute into above formula

arc length

= (60/360) x 2(3.142)( 33) = 34.5 cm