The function g(x) = x2 is transformed to obtain function h:

h(x) = g(x) − 5.

Which statement describes how the graph of h is different from the graph of g?

A.
The graph of h is the graph of g horizontally shifted left 5 units.
B.
The graph of h is the graph of g horizontally shifted right 5 units.
C.
The graph of h is the graph of g vertically shifted down 5 units.
D.
The graph of h is the graph of g vertically shifted up 5 unit

C. The graph of h is the graph of g vertically shifted down 5 units.

Step-by-step explanation:

Given:

The graph of h is different from the graph of g is that the graph of h is the graph of g vertically shifted down 5 units.

We have the general form of transformation:

h (x) = ag(k(x-d)) + c

Because, from the investigation, we noticed that changing the value of c only, and it will cause the function to translate vertically.

When c < 0 (when c is negative), the function is translated downward |c| units.

In this situation, c = -5 so the function is vertically shifted down 5 units.

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.