During a rock concert, the noise level (in decibels) in front row seats has a mean of 92 dB with a standard deviation of 9 dg_ Without
assuming a normal distribution, find the minimum percentage of noise level readings within 8 standard deviations of the mean. (Round
your answer to 2 decimal places.)
Minimum percentage

The minimum percentage of noise level readings within 8 standard deviations of the mean is 98.44%.

Step-by-step explanation:

When we do not know the shape of the distribution, we use the Chebyshev's Theorem to find the minimum percentage of a measure within k standard deviations of the mean.

This percentage is:

Within 8 standard deviations of the mean

This means that . So

The minimum percentage of noise level readings within 8 standard deviations of the mean is 98.44%.

20

step-by-step explanation:

answer: .64

step-by-step explanation

set up the formula for standard deviation for this set of numbers, then simplify