Given:
Triangle MDL
Circle O is inscribed in triangle
m∠M=m∠L=45°
MD = 10
Find: the radius of the circle

10-5

Step-by-step explanation:

As per the attached figure, right angled has an inscribed circle whose center is .

We have joined the incenter to the vertices of the .

Sides MD and DL are equal because we are given that

Formula for area of a

As per the figure attached, we are given that side a = 10.

Using pythagoras theorem, we can easily calculate that side ML = 10

Points P,Q and R are at on the sides ML, MD and DL respectively so IQ, IR and IP are heights of  MIL, MID and DIL.

Also,

So, radius of circle =

infinitely many solutions

step-by-step explanation:

we have been given the equation;

2(2x + 3) = -4 + 2(2x + 5)

we need to determine the value of x.

2(2x + 3), we expand this expression to obtain 4x + 6

similarly 2(2x + 5) will become 4x + 10

now we have;

4x + 6 = -4 + 4x + 10

4x + 6 = 4x + 10 - 4

4x + 6 = 4x + 6

the expression on the left hand side is identical to the one on the right hand side. therefore, we are looking at just a single straight line whose equation is;

y = 4x + 6

consequently, we shall have infinitely many solutions