Find the equation of the line passing through the points (3,3) and (4,5)

y = 2x-3

Step-by-step explanation:

First we find the slope

m = (y2-y1)/(x2-x1)

    = (5-3)/(4-3)

     2/1

The slope is 2

The slope intercept form of the equation is

y =m x+b  where m is the slope and b is the y intercept

y = 2x+b

Substitute a point into the equation

3 = 2(3) +b

3 = 6+b

Subtract 6 from each side

3-6 =b

b = -3

y = 2x-3

answer: ♡♡♡♡♡♡♡♡♡♡

step-by-step explanation: