Write an equation for a circle with a radius of 3 and a center located at point (2,-1)

(x - 2)^2  + (y + 1)^2 = 9

Step-by-step explanation:

recall the equation for a circle:

(x - h)^2 +  (y - k)^2 = r^2

here (h, k) = (2, -1)

and r = 3

so

(x - 2)^2  + (y -(-1))^2 = 3^2

(x - 2)^2  + (y + 1)^2 = 3^2

(x - 2)^2  + (y + 1)^2 = 9

lol.

it's ok we all do this sometimes.

-aparri

step-by-step explanation:

to determine whether a given function is even, we simply substitute x with -x in the expression. if the result after simplification is identical to the original equation, then the function is said to be even other wise odd.

f(-x) = (-x)^2 - (-x) + 8

      = x^2 + x +8

the resulting function is not identical to the original one;

f(-x) ≠ f(x)

therefore, f(x) is not an even function