Jalen Brunson is shooting free throws. Making or missing free throws doesn't change the probability that he will make his next one, and he makes his free throws 90% percent of the time. What is the probability of Jalen Brunson making his next 2 free throw attempts?

The probability is 0.81

Step-by-step explanation:

In this question, we are tasked with calculating the probability that Jalen makes his next two free throws.

P(of making free throw) = 90% = 90/100 or 0.9

P(of missing free throw) = 1 - P( of making free throw) = 1-0.9 = 0.1

Now we want to calculate that probability of making the next two free throws.

That would be = p( of making next throw) * p(of making next two throws) = 0.9 * 0.9 = 0.81

good luck on your studies! : )

david edward.