Graph the x- and y-intercepts and the maximum or minimum of the function f(x)=2|x+3|-4

x-intercepts: -5, -1y-intercept: 2minimum: (-3, -4)

Step-by-step explanation:

The graph is attached.

The vertex of the absolute value function, its minimum, is located at (0, 0). Here, it has been translated left 3 units and down 4 units to (-3, -4). The slope of the lines of the parent function is 1. Here, the vertical scale factor of 2 means the curve rises twice as fast, so only takes 2 horizontal units in either direction from x=-3 to rise the 4 units from the minimum at y=-4 to intersect the x-axis. That is, the x-intercepts are -3-2 = -5, and -3+2 = -1.

In 1 more horizontal unit from x=-1 to the y-axis, the graph rises another 2 units to give a y-intercept of 2.

The x-intercepts are (-5, 0) and (-1, 0)The y-intercept is (0, 2)The minimum of the function is (-3, -4)

I'll do the first one for you. it isn't very hard at all.on number one, you have (50 × 3), which equals 150, and (3 × 3), which equals 9. after you establish that, you add 150 and 9 together. so, (150 + 9) equals 159.this means that 53 × 3 = 159.

Gotta be d the music of previous eras