Consider the equation 2(5x-4) = ax + b
Find a value for a and a value for b so that the equation has only one solution. explain your reasoning.

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a=10

b=-8

Step-by-step explanation:

a=10

b=-8

It's simple. I need my x variable to have a positive coefficient, 10 is already positive; therefore, I simply conclude a = 10. B has to be negative, but in the equation is positive (+b) therefore I need a negative number to make b negative when multiplied (-*+)

2(5x-4) = ax+b

10x-8 = ax+b (Both sides are in the same format so you can substitute in the values)

a =10

b = -8

(2x + 16) + (x) = 180

step-by-step explanation:

given,

abcd is a quadrilateral inscribed in a circle

angle a is labeled x plus 16, (x + 16)

angle b is labeled x degrees, (x)

angle c is labeled 6x minus 4, (6x – 4)

angle d is labeled 2x plus 16, (2x + 16)

what equation can be used to solve for angle b?

we know that the sum of the opposite angles of a simple quadrilateral inscribed in a circle is 180 degrees.

angle b is opposite angle d

therefore, angle b + angle d = 180

(x) + (2x + 16) = 180 

same as (2x + 16) + (x) = 180

other answer is correct. i had used the radius of the radius somehow. a website: