A survey of n = 100 students found that 28 of them were majoring in a STEM field. Give a 95% confidence interval estimate for the true proportion, p, of students who major in a STEM field.

We are 95% that the true proportion of interest for the students were majoring in a STEM field is between 0.192 and 0.368

Step-by-step explanation:

We want to calculate a confidence interval for the true proportion p who represent the % of students were majoring in a STEM field. The best point of estimate for this proportion is given by:

The confidence interval for the true proportion of interest is given by:  

Since the confidence level is 95%, the significance level would be and . The critical values for this case are:

And after replace into the formula we got:

We are 95% that the true proportion of interest for the students were majoring in a STEM field is between 0.192 and 0.368

the two may have that, even a breakdown is probably offered

37/3

step-by-step explanation:

step 1: simplify both sides of the equation.

7x+8(x+

1

4

)=3(6x−9)−8

7x+(8)(x)+(8)(

1

4

)=(3)(6x)+(3)(−9)+−8(distribute)

7x+8x+2=18x+−27+−8

(7x+8x)+(2)=(18x)+(−27+−8)(combine like terms)

15x+2=18x+−35

15x+2=18x−35

tep 2: subtract 18x from both sides.

15x+2−18x=18x−35−18x

−3x+2=−35

step 3: subtract 2 from both sides.

−3x+2−2=−35−2

−3x=−37

step 4: divide both sides by -3.

−3x

−3

=

−37

−3

x=

37

3