Convert the rectangular equation to polar form
X^2 + y^2 - 6y = 0

A. r= 6cos
B. r= 6sin
C. r^2= 6cos
D. r^2= 6sin
E. r^2= 6y

Show your work

step-by-step explanation:

use pothagarean therom

a^2+b^2=c^2 so first ac

acm is a right triangle because c= 90°

and am (the hypotenuse or c) =16+9 =25

but there is not enough info we need another angle or side length

slope intercept form is y = mx + b

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