In the Volume of Pyramids section, a right square pyramid has a slant height of 5cm and a base edge length of 6cm. Select all that apply. *
B = 6cm
B= 36cm squared
The height and the slant height form a right triangle.
h = 4cm
h= 7cm
h = 3cm
V = 1/3Bh
V = Bh
V = 144 cm cubed
V = 48 cm cubed

B = 36 cm²

h = 4 cm

V = B*h/3

V = 48 cm³

Step-by-step explanation:

B refers to the area of the base of the right square pyramid which is an square. Given that it has a base edge length of 6 cm, then:

B = 6² = 36 cm²

Between height (h), slant height (l) and half of base edge (s/2) of the pyramid a right triangle is formed. From Pythagorean theorem:

l² = h² + (s/2)²

h = √[l² - (s/2)²]

h = √[5² - (6/2)²]

h = 4 cm

The volume of the pyramid is computed as follows:

V = B*h/3

V = 36*4/3

V = 48 cm³