Write an equation of the line that passes through point (5,6) and has a slope of 2. A) y = 10 + b B) y = 2x - 4 C) y = 2x + 4 D) y = -5x + 2

y= 2x-4

Step-by-step explanation:

We can use the slope intercept form of a line

y = mx+b

Where m is the slope and b is the y intercept

y =2x+b

Substitute the point into the equation

6 = 2(5) +b

6 = 10+b

Subtract 10 from each side

6-10 = 10-10+b

-4 =b

y= 2x-4

the equation of the parallel line would be y = 2x + 9

step-by-step explanation:

to start we need to find the slope of the original line. we can do that by looking at the coefficient of x, which is 2

since the slope of the original line is 2 and parallel lines have the same slope, we know the new line will also have 2 slope. now we can use that along with the point given in point-slope form to get the find equation.

y - y1 = m(x - x1)

y - 5 = 2(x + 2)

y - 5 = 2x + 4

y = 2x + 9