A car moved at a speed of 90km/hr for 3 minutes. What distance did it cover?

270kilometers

Step-by-step explanation:

To find the distance, all you have to do is the speed · time

In these types of distance time and word problems, you multiply the other factors, 90 and 3, The time(T) · The speed(S)

So. 90(S) · 3(T) = 270(D)

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

this is a very good question

step-by-step explanation:

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