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The width of a rectangle is 1 units less than the length. The area of the rectangle is 56 units. What is the width, in units, of the rectangle?

7

Step-by-step explanation:

Area is found by multiplying the length and the width.

Let's think about the factors of 56.

The only whole number pairs that can be multiplied to get 56 are

1 x 56, 2 x 28, 4 x 14, and 7 x 8.

There's only one pair where the width is less than the length, 7 x 8.

The width is always the smaller number of the two, so the width must be 7.

step-by-step explanation:

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.