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Mathematics, 05.05.2020 05:28 XxLydiaxXwolf773

Consider the following series. [infinity] n = 1 3n + 14βˆ’n Determine whether the geometric series is convergent or divergent. Justify your answer. Converges; the series is a constant multiple of a geometric series. Converges; the limit of the terms, an, is 0 as n goes to infinity. Diverges; the limit of the terms, an, is not 0 as n goes to infinity. Diverges; the series is a constant multiple of the harmonic series.

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Consider the following series. [infinity] n = 1 3n + 14βˆ’n Determine whether the geometric series is...
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