What are the degree and zeros of the polynomial f(x) = (x - 2)"?
a. degree 5; zeros 2,-1
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Mathematics, 05.05.2020 06:23 idc23
What are the degree and zeros of the polynomial f(x) = (x - 2)"?
a. degree 5; zeros 2,-1
C. degree 3; zeros 1, 2,
b. degree 5; zeros 1, 2,
d. degree 5; zero 2
Answers: 2
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Refer to the table below if needed. second quadrant third quadrant fourth quadrant sin(1800- - cos(180° -) tan(180°-e) =- tane cot(1800-0) 10 it to solo 888 sin(180° +c) = - sine cos(180° +) =- cose tan(180° +c) = tane cot(180° +o) = cote sec(180° + c) = - seco csc(180° +2) = - csce sin(360° -) =- sine cos(360° -) = cose tan(360° - e) =- tane cot(360° -) = -cote sec(360° -) = seco csc(360° -) = csco sec(180° -) = csc(180° -) = csca 1991 given that sine = 3/5 and lies in quadrant ii, find the following value. tane
Answers: 2
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Which two undefined geometric terms always describe figures with no beginning or end?
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