You have five $1 bills, four $5 bills, six $10 bills, and three $20 bills you select a bill at random, without replacing the bill what is the probability of a 1 then a ten?
a.11/35
b.5/51
c.5/54
d.193/306

Option B.

Step-by-step explanation:

It is given that,

Number of $1 bills = 5

Number of $5 bills = 4

Number of $10 bills = 6

Number of $20 bills = 3

So,

Total number of bills = 5 + 4 + 6 + 3 = 18

We need to find the probability of a 1 then a ten (without replacement).

Probability of selecting $1 bill in first draw

After one draw, the number of remaining bills is 18 - 1 = 17.

Probability of selecting $10 bill in second draw

The probability of a 1 then a ten is

Therefore, the correct option is B.

(0,-3) see attached graph

step-by-step explanation:

a. to solve the system, graph the two equations.

x = y+3 becomes y=x-3 has m=1/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move up 1 unit and 1 unit to the right. plot a point and connect.

y=-4x+3 has m =-4/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move down four units and to the right 1 unit. plot a point and connect.

the solution is the point (x,y) where the two lines intersect. by the graph below it is (0,-3).

b. to solve by substitution, substitute y = -4x-3 into x= y+3

x= (-4x-3) +3

x=-4x

5x=0

x=0

now substitute x = 0 back in to find y.

y= -4(0)-3

y=0-3

y=-3

solution is (0,-3)

c. use elimination by adding the equations together.

x-y=3

4x+y=-3

5x=0

x=0

then substitute into one equation to find y.

y=-4(0)-3

y=-3

step-by-step explanation: