1. 4(k-8)=-32+4k
2, 6x+3-6x=3
3.:-28=-7(3x+4)+21x
4. 8(k-6)+58=2(4k+5)
5.12+4n=4(n+3)
6.-5(x-1)=5-5x
Can someone tell me if any of these have no solution, infinite solution

wait this depends wether emily and zach how they are thinking.

yes they are the same.

1st integer x

2nd integer x+1

3rd integer x+2

4th integer x+3

x+x+1 +x+2+x+3 =74

combine like terms

4x+6 = 74

subtract 6 from each side

4x = 68

x = 17

the integers are 17,18,19,20

i believe the answer is y=0.25x+-3