Alvin has a prism-like water tank whose base area is 0.9 square meters and height is 0.6 meters. He wants to buy guppy fish, and the pet store owner tells him to make sure their density in the tank isn't more than 5 fish per cubic meter. How many fish can Alvin get, at most?

Alvin can't have more than 2 fishes on his tank.

Step-by-step explanation:

In order to calculate how many fish Alvin can have in his tank we first need to calculate the volume of the tank. A prism's volume is given by the following formula:

v = Abase*h

Therefore for Alvin's, we have:

v = 0.9*0.6 = 0.54 m³

Since he can't have more than 5 fish per cubic meter we can use a rule of three in a way that:

5 fish -> 1 m³

x fish -> 0.54 m³

5/x = 1/0.54

x = 0.54*5 = 2.7

Since he can't have a 0.7 fish and in order to mantain the density to the recommended level, he can't have more than 2 fishes.

according to the triangle sum theorem, all the angles in a triangle must add up to 180 degrees. if we know one angle is already 90, we do 180-90=90. the other 2 angles must add up to 90, exactly.

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alright well the answers to your question is

2xy/9 hope this have a nice day : )

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