The net below can be folded to form a square pyramid.

A square pyramid. The square base has side lengths of 9 inches. The triangular sides have a height of 6.1 inches and side length of 7.6 inches.

What is the surface area of the pyramid?
190.8 square inches
217.8 square inches
300.6 square inches
354.6 square inches

190.8 square inches

Step-by-step explanation:

The area of one of its triangular sides is given by A = bh/2 were b = base = 9 inches and h = perpendicular height = 6.1 inches.

A = bh/2. Since we have 4 triangular sides, the total area of its sides  A₁ = 4A = 4bh/2 = 2bh = 2 × 9 × 6.1 = 109.8 square inches.

The area of is base is the area of a square = 9² = 81 square inches.

So te total surface area is 109.8 square inches + 81 square inches = 190.8 square inches

190.8

Step-by-step explanation:

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step-by-step explanation:

other answer is correct. i had used the radius of the radius somehow. a website: