In circle A shown, secant DE and tangent DG are drawn. It ir know that m BAC = 63 and mBE = 96.

Givens

is secant.

is tangent.

Remember that the arc subtended by a central angle is equal to it. That means

Now, by sum of arcs, we know

By definition, the total arc of a circle is 360°, so

We know that the external angle formed by a secant and a tanget is one half of the difference between the intercepted arcs, so

So, the angle D is 69°.

hello from mrbilldoesmath!

answer:

a(n) - a(n-1) -3

discussion:

this ones a bit interesting. given a(n) = 5 - 3n consider this:

a(n-1) = 5 - 3(n-1)

          = (5 - 3n) + 3             => but a(n) = 5 - 3n, the first term

          = a(n)   + 3                 => subtract 3 from both sides

a(n-1) -3 = a(n)  

or

a(n) - a(n-1) -3

you,

mrb

idk

step-by-step explanation: