NEED HELP ASAP A survey was conducted with high school students in
each grade to see how many prefer math or science.
Some of the data are shown below.
Which statement is true about the joint frequencies in
this table?
40
11 | 12 |
Total
O Twenty-three 9th graders and fifteen 11th graders
prefer math.
O Fourteen 11th graders prefer math and eight 10th
graders prefer science.
O Thirty-five 12th graders prefer math and nine 10th
graders prefer science.
Twenty-three 9th graders and thirty-two 12th
graders prefer math.
Math
18
90
Science 40
15
95
Total
63
26
29
67
185

Question:

a. Twenty-three ninth graders and fifteen eleventh graders prefer math.

b. Fourteen eleventh graders prefer math and eight tenth graders prefer English.

c. Thirty-five twelfth graders prefer math and nine tenth graders prefer English.

d. Twenty-three ninth graders and thirty-five twelfth graders prefer math.

e. Eighteen tenth graders prefer English and fourteen eleventh graders prefer math.

Therefore, the correct options are;

b. and d.

Step-by-step explanation:

Here we have a table with blank boxes and totals from which we can fill the boxes;

For the 12th graders, we have a total of 67 pupils with 32 preferring English, therefore the number of the 12th graders that prefer math is 67 - 32 = 35 pupils

Similarly for the 11th graders we have total pupils = 29 with 15 preferring English, therefore the number of the 11th graders that prefer math is 29 - 15 = 14 pupils

Also for the 10th graders we have total pupils = 26 with 18 preferring math, therefore the number of the 11th graders that prefer English is 26 - 18 = 8 pupils

Finally for the 9th graders, we have a total of 63 pupils with 40 preferring English, therefore the number of the 9th graders that prefer math is 63 - 40 = 23 pupils

From the above, the correct option is

b

step-by-step explanation:

the total is 23.97. 0.25% is off so you have to subtracting 25% from 100% and you will get 75% if you convert it to decimal you will get 0.75. you have to find the original because the formula is % times original = total.so you have the total and the % so you just have to plug it in.

maybe i can