Solve (x + 2 < 5) ∩ (x - 7 > -6).
{x | 1 < x < 3}
{x | x < 3 or x &...
Mathematics, 05.05.2020 10:58 Brennen435
Solve (x + 2 < 5) ∩ (x - 7 > -6).
{x | 1 < x < 3}
{x | x < 3 or x > 1}
{all real numbers}
Answers: 2
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Answers: 3
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