Suppose the tank shown has a length of 2 feet, a width of 1 foot, and is filled with water to a depth of 8 inches. a stone is placed in the tank and fully submerged, causing the water level to rise by 2 inches. what is the volume of the stone?

The volume of the stone is 576 cubic inches

Step-by-step explanation: The dimensions of the tank are given in feet and inches, hence we shall use the lower of the unit of measurement that is, inches. Note that 1 foot equals 12 inches, so the length is 2 feet times 12, which equals 24 inches. Also the width is 1 foot times 12 which equals 12 inches. Then the tank is filled with water up to a depth of 8 inches , so the volume of water in the tank can be calculated as follows;

Volume = L x B x H

Where Length = 24, Width = 12 and Height = 8

Volume = 24 x 12 x 8

Volume = 2304

At 2304 cubic inches, a stone is placed in the water tank and the water level rises by 2 inches which implies that the depth is now 10 inches. With the addition of the stone, the dimensions are now shown as;

Length = 24, Width = 12, and Height = 10

Volume = L x W x H

Volume = 24 x 12 x 10

Volume = 2880

With the rise in volume of water in the tank, the difference (which is the volume of the stone) now is Volume with stone minus volume without stone, that is

Volume of stone = 2880 - 2304

Volume of stone = 576

Therefore the volume of the stone is 576 cubic inches

this was already solved by me with a different person. if you look it up in the search bar at the top of the page, you will get the answer.

step-by-step explanation:

step-by-step explanation:

a rhombus is a parallelogram enjoying his symmetry.