A bag contains 4 red marbles, 3 blue marbles and 6 green marbles. If two marbles are
drawn out of the bag, what is the probability, to the nearest 100oth, that both
marbles drawn will be red?

Step-by-step explanation:Total marble = 4+6+7 = 17Number of green = 7Prob(1st green) = 7/17Now their are 6 green left and 16 marbleProb(2nd green) = 6/16 = 3/8Now their are 5 green left and 15 marbleProb(3rd green) = 5/15 = 1/3Prob(1st and 2nd and 3rd green) will be = 7/17 × 3/8 × 1/3= 7/(17×8)= 7/136.

Step-by-step explanation:

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.

how do heroes resolve conflicts in beowulf?

question 15 options:

they sue each other in court

they get a mediator

the seek counseling

they get even or take revenge

step-by-step explanation: