Suppose a certain baseball diamond is a square 65 feet on a side. The pitching rubber is located 41.5 feet from home plate on a line joining homeplate and second base.

a. How far is it from the pitching rubber to first base?
b. How far is it from the pitching rubber to second base?
c. If a pitcher faces home plate, through what angle does he need to turn to face first base?

Step-by-step explanation:

Notice that a baseball diamond is a square, which means all sides are equal. In this case, each side is 65 feet long.

It's important that a square is a symmetric figure, as a symmetric quadrilateral, its diagonals are congruent and the bisect each other. That means that the distance from every corner to the center is the same.

a. Based on square definitions, the distance from the pitching rubber to first base is 41.5 feet.

b. Based on square definitions, the distance from the pitching rubber to second base is 41.5 feet.

c. if the pitcher faces the home plate, he needs to turn his 90° to face the first base, that is because diagonals are perpendicular each other, which means they have a right angle between.

what is

step-by-step explanation:

i believe that the answer is

b. y-1=-2(x-4)

hope this !