Felix tried to solve an equation step by step. \qquad\begin{aligned} 2(5g-1)&=3 \\ 5g-1&=1.5&\green{\text{Step } 1} \\ 5g&=2.5&\blue{\text{Step } 2} \\ g&=0.5&\purple{\text{Step } 3} \end{aligned} 2(5g−1) 5g−1 5g g =3 =1.5 =2.5 =0.5 Step 1 Step 2 Step 3 Find Felix's mistake. Choose 1 Choose 1

step-by-step explanation:

y = | -2(-2) |     →     y = | 4 |     →     y = 4       ⇒   (-2, 4)

y = | -2(-1) |     →     y = | 2 |     →       y =   2       ⇒   (-1, 2)    

y = | -2(0) |     →     y = | 0 |     →       y = 0         ⇒   (0, 0)

y = | -2(1) |   c →     y = | -2 |     →     y =   2         ⇒   (1, 2)    

y = | -2(2) |     →     y = | - 4 |     →     y =   4         ⇒   (2, 4)  

hello!

to begin with, we're given that on earth, a rock weighs 20 pounds, and while on jupiter, that same rock weighs 42 pounds. now, we're trying to find the weight of a rock that weighs 10.5 pounds on earth, on jupiter.

to solve this, first, set up a proportion, cross-multiply, and solve it algebraically.

setting up the proportion is the hardest and the most confusing part of the problem, but it's simple.

if on earth, the rock weighs 20 lbs, and on jupiter it weighs 42 lbs, our first part of our proportion is 20/42 lbs. the second part has to be equal to each other. this means that 10.5 has to be on the numerator of the fraction, and x, the value we're trying to find, has to be on the denominator. remember that the rock weighs 10.5 lbs on earth, and we're trying to find the weight of it on jupiter (which is x).

20/42 = 10.5/x

next, you would cross-multiply.

20x = 42(10.5)

20x = 441

now, solve it algebraically by using division.

x = 22.05 lbs

this can be rounded to 22.1 lbs.

therefore, the weight of the rock on jupiter is 22.1 lbs, the fourth choice.

3 4 7 12 19

+1 +3 +5 +6

i would guess 26 because this isnt a sequential pattern or its to short to know

1875cm³

step-by-step explanation:

we have a 20 × 20 × 5 container with (what im guessing is a) 5 × 5 × 5 hole in the center. first, we need to calculate the volume of the 20 × 20 × 5 container.

20 × 20 × 5 = 2000cm³

now, we need to calculate the volume of the hole.

5 × 5 × 5 = 125cm³

now to find the area of the container, we take to solid area of the container, and subtract the area of the hole.

2000cm³ - 125cm³ = 1875cm³