Solve for xif 2(5 +252 =48.
0 1= -2+24 and x = =2-324
0 x = -2+4 and x = -2-2V24
e1 = -2+2 and x = =2-2
2
= =2+2V5 and 1 = -2 - 26

x=-2+2 sqrt 6 divided by 5

Hoor this helps

Step-by-step explanation:

the number of possible outcomes that do not show a 1 on the first spinner and show the number 4 on the second spinner is 2.

spinner 1 spinner 2

1                     1

1                     2

1                     3

1                     4

2                   1

2                   2

2                   3

2                   4   = not 1, and 4

3                   1

3                   2

3                   3

3                   4 = not 1, and 4

only 2 outcomes have passed the given condition.

step-by-step explanation: