Find the solutions to the equation by completing the square.
x² - 6x=7
x² - 6x = 7
(x- _)2 =
x-3=1
x-3= _
and x - 3 =
What is the largest value of x?
What is the smallest value of x?

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.

"image"

step-by-step explanation:

in most of these problems, the notation is that the point with a "prime" is the image of the point without. that is, b' is the image of b.

here, there is no dilation or reflection. there is simply translation (with no direction shown). which figure you call the "preimage" and which one you call the "image" is up to you. as a matter of convention, the naming is as described above.

i think the answer is a.( -3, -1 )