A solid is composed of squares and equilateral triangles. Its net is shown below: A triangular prism and its net are shown. The net is three squares wif side length 5 units. Attached above and below the middle square are equal sized triangles. The area of each triangle is 11 square units. The surface area of the triangular prism is square units.

62sq units

Step-by-step explanation:

4² = 16 sq>16(3) = 48 sq

*the area of each triangle is 7sq*

*the area the two triangles together: 2(7) = 14 sq

adding these together turns the surface area 14+48 = 62 sq

Therefore your answer is 62 sq units

The answer is 62

Step-by-step explanation:

Hope I helped have a good rest of your day Happy Friday!!!

options a,b,c are the right answer.

step-by-step explanation:

a linear parent function is always represented as y = x

if we write this function in the form of y=mx+c

⇒

or  

now if we plot a graph we will find these characteristics:

1) y intercept of the graph is zero so its a straight line passing through origin.

2) as we can see in both the forms of function written, values of x and y may be either positive or negative for the positive slope means points on the graph are either in first quadrant or in third one.

3) it's slope is one.

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°