x2 - 6x = -y2 - 12y - 9
Mathematics, 05.05.2020 15:09 lilyclairehutson
What is the center of the circle given by the equation below?
x2 - 6x = -y2 - 12y - 9
A.
(3 , -6)
B.
(-3 , -6)
C.
(3 , 6)
D.
(-3 , 6)
Answers: 1
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What is the center of the circle given by the equation below?
x2 - 6x = -y2 - 12y - 9
x2 - 6x = -y2 - 12y - 9
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