On Monday, Josh went to the Farmer's Market. He bought 55 peaches and 22 watermelons for $7.75.. On Thursday, Josh went back to the Farmer's Market and bought 33 peaches and 44 watermelons for $10.95. What systems of equations can be used to determine the cost for one peach (p)(p) and one watermelon (w)?

The system of equations is

When solved

Step-by-step explanation:

Let the price of one peach =p

Let the price of one watermelon=w

On Monday, bought 5 peaches and 2 watermelons for $7.75.

On Thursday, Josh went back to the Farmer's Market and bought 3 peaches and 4 watermelons for $10.95.

The system of equation that could be used to solve for the price of one peach (p) and one watermelon (w) is therefore:

To solve this, Multiply the first equation by 4 and the second equation by 2.

Subtract

14p=9.1

Divide both sides by 14

p=$0.65

Next, we substitute p=$0.65 in any equation to obtain w.

5p+2w=7.75

5(0.65)+2w=7.75

2w=7.75-3.25

2w=4.5

w=$2.25

Therefore:

the revenue of the fitness center, y, is the product of two factors: the number of members and the fee paid by each member. there are 320 members now, but number of members goes down by 10 for each $5 increase in fees, so if x is the number of $5 price increases then members is equal to (320 - 10x). since the fee is currently $45, and the fee increases by $5 for every price bump x, the fee is given by (45 + 5x). so, revenue y is given by y = (320 - 10x)(45 + 5x).

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step-by-step explanation: