As a result of the tide, the depth of the water in the bay varies with time,. According to the harbourmaster the depth can be modeled by the function d(t)=2.5cos(pi/6)(t-2)+4, where t is the number of hours since midnight and d is the depth in meters, need Amplitude, Period, Phase shift, equation of midline

The amplitude = 2.5 metres

Period = t -2

Phase shifts = 4

Equation of the midline

= (pi/6)(t-2)+4

Step-by-step explanation:

If according to the harbour master the depth was modeled by the function

d(t)=2.5cos(pi/6)(t-2)+4,  then

The amplitude = 2.5 metres

Period = t -2

Phase shifts = 4

Equation of the midline = (pi/6)(t-2)+4

answer: the price of one pound cabbage = $ 0.8

the point (10,8) represents that the cost of 10 pounds cabbage is $ 8

step-by-step explanation:

since, here is a proportional relation between the number of pounds of cabbage (x) and the price in dollars (y).

therefore, we can write,

⇒ y = k x

where k is the constant of proportionality.

now, point (5,4) is in the line.

thus, it will satisfies the above equation of line.

⇒ 4 = 5 k

⇒ k = 0.8

thus, the equation of the line is,

y = 0.8 x

a) for x = 1,

y = 0.8

therefore, the cost of one pound of cabbage is 0.8 dollars.

b) in the below graph (10,8) represents that the cost of 10 pounds of cabbage is 8 dollars.

(x+3)(x+7)

step-by-step explanation: