Mathematics, 05.05.2020 15:59 Chad5978

A cell phone weighs about 2.8 times 10 Superscript n pounds. Which value of n is most reasonable? Negative 3 Negative 1 0 1

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Answer from: offshoreext

-1

Step-by-step explanation:

The weight of the cell phone is given by:

W=2.8*10^n

The options provided for 'n' are:

a. -3

b. -1

c. 0

d. 1

Applying the possible values:

$W_a=2.8*10^{-3}\\W_a = 0.0028\ pounds\\\\W_b=2.8*10^{-1}\\W_b = 0.28\ pounds\\\\W_c=2.8*10^{0}\\W_c = 2.8\ pounds\\\\W_d=2.8*10^{1}\\W_d = 28\ pounds$

A cellphone could not possibly weigh as little as 0.0028 or as much as 2.8 or 28 pounds. Therefore, the most reasonable value for n is -1.

Answer from: roseemariehunter12

(B)-1

Step-by-step explanation:

Let us plug in the given values into 2.8X10^n $2.8X10^{-3}=2.8X 0.001=0.0028\:Pounds\\2.8X10^{-1}=2.8X 0.1=0.28\:Pounds\\2.8X10^{0}=2.8X 1=2.8\:Pounds\\2.8X10^{1}=2.8X 10=28\:Pounds$

A reasonable value for the weight of a cell phone will be 0.28 Pounds.

Therefore, n=-1

Answer from: Quest

i think the answer is true

step-by-step explanation:

Answer from: Quest

answer: the proof is mentioned below.

step-by-step explanation:

since, given: lines bc = ef

prove: lines ac > ef

statements reason

1. bc=ef 1. given

2. ac= ab+bc 2. because b is the point between the

line segment ac

3. ac > bc 3. because if a line segment is equal to

the sum of two line segments then it is

always greater then each of these

individual line segments

4. ac > ef 4. by equality property.

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A cell phone weighs about 2.8 times 10 Superscript n pounds. Which value of n is most reasonable? Ne...