Mathematics, 05.05.2020 16:00 Shubbs
A charge q1 = 5 μC, is at the origin. A second charge q2 = -3 μC is on the x-axis 0.8 m from the origin. The electric field at a point on the y-axis 0.5 m from the origin is:
Answers: 3
![\vec{E}=\vec{E_1}+\vec{E_2}=[25856\hat{i}+163443.2\hat{j}]N/C](/tpl/images/0639/9286/12f1f.png)
![\vec{E_2}=Excos\theta \hat{i}-Eysin\theta \hat{j}\\\\\theta=tan^{-1}(\frac{0.5}{0.8})=32\°\\\\r=\sqrt{0.5^2+0.8^2}=0.94m\\\\\vec{E_2}=(8.89*10^9Nm^2/C^2)\frac{(-3*10^{-6C})}{(0.94m)^2}[cos(32)\hat{i}-sin(32)\hat{j}]\\\\=[25856.06\hat{i}-16156.71\hat{j}]N/C](/tpl/images/0639/9286/71dd2.png)
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A charge q1 = 5 μC, is at the origin. A second charge q2 = -3 μC is on the x-axis 0.8 m from the ori...
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