The following definitions are used: a relation on a set A is defined to be irreflexive if, and only if, for every x A, x R x; asymmetric if, and only if, for every x, y A if x R y then y R x; intransitive if, and only if, for every x, y, z A, if x R y and y R z then x R z. The following relation is defined on the set A = {0, 1, 2, 3}. Determine whether the relation is irreflexive, asymmetric, intransitive, or none of these. (Select all that apply.) R2 = {(0, 0), (0, 1), (1, 1), (1, 2), (2, 2), (2, 3)}

IT IS ASYMMETRIC.

Step-by-step explanation:

Here we will consider all options to determine which of our options holds true.

Given set A;

А - {0, 1, 2}

R {(0,0), (0, 1), (0, 2), (1,2))

Let us not fail to keep the conditions given in the question at heart;

To Check for intransitive;

This condition holds true for all x, y, z belonging to A has -

(1) (x, y)and (y, z) but not (x, z) in R5OR

(2) don't have (x, y) in R5 OR

(3) (x, y)but don't have (y, z) in R5,

for 0, 1, 2 we have (0, 1) and (1, 2) but also have (0, 2) in R5 .

Condition failed here so, no need to check ahead.

⇒ So, It is NOT Intransitive.

To Check for irreflexivity;

This condition holds true for all x belonging to A -

(1) don't have (x, x) in R5,

for 0 we have (0, 0) in R5 so the condition is failed right here So, no need to check further for irreflexivity.

⇒ So, It is NOT Irreflexive.

Now let's Check for asymmetric,

This condition holds true for all x, y belonging to A has -

(1) (x, y) in R5 but not (y, x) OR

(2) don't have (x, y) in R5,

for 0, 1 we have (0, 1) in R5 but do not have (1, 0),

for 1, 0 we don't have (1, 0) in R5

for 1, 2 we have (1, 2) but not (2, 1) in R5

for 2, 1 we don't have (2, 1) in R5

for 0, 2 we have (0, 2) in R5 but not (2, 0)

finally for 2, 0 we don't have (2, 0) in R5

So, Condition satisfied for every г.уеА

⇒ IT IS ASYMMETRIC.

cheers i hope this helps

answer: h

step-by-step explanation:

(b) 240

step-by-step explanation:

first, we use the pythagorean formula using the given side lengths to find x. then we use x to find the side lengths. then we add the side lengths to find the perimeter.

pythagorean theorem formula:

a^2 + b^2 = c^2

(x - 20)^2 + (x - 40)^2 = x^2

x^2 - 40x + 400 + x^2 - 80x + 1600 = x^2

x^2 -120x + 2000 = 0

(x - 100)(x - 20) = 0

x - 100 = 0 or x - 20 = 0

x = 100 or x = 20

we see that the solution x = 20 must be discarded because it will give a negative side length and a side length of 0. the only valid solution is x = 100.

perimeter = sum of the lengths of the sides

perimeter = x + x - 20 + x - 40

perimeter = 3x - 60

replace x with 100.

perimeter = 3(100) - 60

perimeter = 300 - 60

perimeter = 240