A lomy owner has his own fuel supply and needs to refill his storage tank. He has just completely

filled the fuel tank of the lorry with 170 litres from empty. He now has 100 litres of fuel left in his

storage tank. With the price of fuel expected to fall soon he only wants to buy enough for the next

fortnight. Normally his regular short daily trips total 300 km and this leaves just 20 litres in the

lorry's fuel tank. He expects to complete three regular days of 300 km journeys each week, but

this could rise to five. Sometimes the total journeys are longer but his daily trips never total more

than 400 km in a day. He never works more than five days in a week. His storage container holds

4000 litres

How much fuel should he order to be certain that he has enough for the next two weeks?

He should order for 1046.67 litres fuel to be certain that he has enough for the next two weeks

Step-by-step explanation:

Note that he has just completely

filled the fuel tank of the lorry with 170 litres from empty. He now has 100 litres of fuel left in his storage tank

If his regular short daily trips total 300 km and this leaves just 20 litres in the lorry's fuel tank.

That is 100 litres -20 litres = 80 litres

On 300km, he consumed 80 litres

He plans to complete three regular days of 300 km journeys each week, but this could rise to five. Sometimes the total journeys are longer but his daily trips never total more than 400 km in a day. He never works more than five days in a week. His storage container holds

4000 litres

From all these analysis, we can deduce that the maximum km of journey he should prepare for is

400km × 5 = 2000km for one week

Since he consumed 80 litres of fuel for any 300km

Then,

80/300 = L/2000

L = 1600/3

L = 533.33 litres

The journey for two weeks will be

533.33 × 2 = 1066.67 litres

Recall that he left 20 litres in the tank. Take this away from 1066.67 litres.

1066.67 - 20 = 1046.67 litres

He should therefore order for 1046.67 litres fuel to be certain that he has enough for the next two weeks

area of part 1:

a1=base*height/2=(8+2)*(8-2-2-1)/2=10*3/2=15 ft^2

area of part 2:

a2=length*width=(8+2)*1=10 ft2

area of part 3:

a3=length*width=8*2=16 ft2

total shaded area : a1+a2+a3=41 ft2

total area of the reactangle : a=16*8=128 ft2

total area of the nonshaded region : 128-41=87 ft2

d, x=8

step-by-step explanation:

simplifying

4x + -5 = 2x + 11

reorder the terms:

-5 + 4x = 2x + 11

reorder the terms:

-5 + 4x = 11 + 2x

solving

-5 + 4x = 11 + 2x

solving for variable 'x'.

move all terms containing x to the left, all other terms to the right.

add '-2x' to each side of the equation.

-5 + 4x + -2x = 11 + 2x + -2x

combine like terms: 4x + -2x = 2x

-5 + 2x = 11 + 2x + -2x

combine like terms: 2x + -2x = 0

-5 + 2x = 11 + 0

-5 + 2x = 11

add '5' to each side of the equation.

-5 + 5 + 2x = 11 + 5

combine like terms: -5 + 5 = 0

0 + 2x = 11 + 5

2x = 11 + 5

combine like terms: 11 + 5 = 16

2x = 16

divide each side by '2'.