The amount of Jen's monthly phone bill is normally distributed with a mean of $59 and a standard deviation of $10. What percentage of her phone bills are between $29 and $89?

And we can find this probability with this difference:

And in order to find these probabilities using the normal standard distribution or excel and we got.  

So we expect about 99.735% of values between $29 and $89

Step-by-step explanation:

Let X the random variable that represent the amount of Jens monthly phone of a population, and for this case we know the distribution for X is given by:

Where and

We are interested on this probability first in order to find a %

The z score is given by:

If we apply this formula to our probability we got this:

And we can find this probability with this difference:

And in order to find these probabilities using the normal standard distribution or excel and we got.  

So we expect about 99.735% of values between $29 and $89

1. is 4 and 2. is 3

step-by-step explanation:

so if you look at the first one you see that 1 is to 4 and 2 is to 8 and so on, so you can see for every 1 there is a times 4 so if it were 3 then it would be 3*4 and it is 12

for number 2 it is 3 because 1 is to 3 and 2 is to 6 so for every 1 there is 3 so if it were 3 then there would be 3*3 = 9

answer: i guess 105 degrees?

step-by-step explanation: