The mean height of an adult giraffe is 18 feet. Suppose that the distribution is normally distributed with standard deviation 0.8 feet. Let X be the height of a randomly selected adult giraffe. Round all answers to two decimal places. What is the probability that a randomly selected giraffe will be shorter than 17 feet tall?What is the probability that a randomly selected giraffe will be between 16 and 19 feet tall? The 90th percentile for the height of giraffes is?

1. the probability that giraffe will be shorter than 17 feet tall is equal to 0.1056

2. the probability that a randomly selected giraffe will be between 16 and 19 feet tall is equal to 0.8882

3. the the 90th percentile for the height of giraffes is 19.024

Step-by-step explanation:

To calculate the probability that a giraffe will be shorter than 17 feet tall, we need to standardize 17 feet as:

Where x is the height of the adult giraffe, m is the mean and s is the standard deviation, so 17 feet is equivalent to:

Now, the probability that giraffe will be shorter than 17 feet tall is equal to P(z<-1.25). Then, using the standard normal distribution table, we get that:

At the same way, 16 and 19 feet tall are equivalent to:

So, the probability that a randomly selected giraffe will be between 16 and 19 feet tall is equal to:

Finally, to find the the 90th percentile for the height of giraffes, we need to find the value z that satisfy:

Now, using the standard normal distribution table we get that z is equal to 1.28. Therefore, the height x of the giraffes that is equivalent to 1.28 is:

it means that the the 90th percentile for the height of giraffes is 19.024

ok then what happened.

answer: r there any options?

step-by-step explanation: