Rewrite the following equation in the center-radius form of the equation of a circle.
x2 + 12x + y2 + 10y = -45

A.
(x + 6)2 + (y + 5)2 = 16
B.
(x - 5)2 + (y - 6)2 = 16
C.
(x + 8)2 + (y + 4)2 = 16
D.
(x + 6)2 + (y + 6)2 = 16

A

Step-by-step explanation:

observe

x² + 12x + y² + 10y = –45

add 36 + 25 on both side

x² + 12x + 36 + y² + 10y + 25 = –45 + 36 + 25 = 16

(x + 6)² + (y + 5)² = 16

the transverse axis of a hyperbola is the line that contains the two vertices and the two focuses.

in this example (hyperbola of equation x^2/2 - y^2/4 = 1), the transverse axis is the  x-axis  . 

step-by-step explanation: