An object is launched from the ground the objects height in feet can be described by the quadratic function HT equals 80t -16t^2, where t is the time in seconds, since object is launched when will the object hit the ground after his launch explain how you found your answer

The object will hit the ground after 5 seconds. You can rewrite the quadratic function as a quadratic equation set equal to zero to find the zeros of the function 0 = –16t2 + 80t + 0. You can factor or use the quadratic formula to get t = 0 and t = 5. Therefore, it is on the ground at t = 0 (time of launch) and then hits the ground at t = 5 seconds.

hi friend

here is your answer

there are two angles that are alternate interior angle with angle 9

the angle 15 and angle 7 are alternate interior angle with angle 9.

hope it is for you so mark my answer as a brainliest

you probably already have the answer but anyways it's b. 15.0

step-by-step explanation: